Introduction to Operational Amplifiers
It is complete amplifier which is configurable using external components for desired applications. It was originally designed for various type of mathematical operations. Circuits can be built to perform Multiplication. Division. Addition subtraction, Logarithmic manipulations, Integration, Differentiation etc. It can be used to perform signal amplification, attenuation, Oscillator, Filters, Comparator, Signal generator and many other applications.
It is very easy to tailor this amplifier for various application. The Symbol and a picture of very popular 741 Op-Amp is given below.
|
|
|
The ideal Op-Amp has the following Characteristics.
Open loop gain AV is infinite i.e. , AV = ∞
Its input Resistance is Infinite.
Out put resistance is zero.
It has an infinite bandwidth
|
These characteristics are nor achievable practically. In reality these properties set a benchmark for the evolution of high performance Op-Amps.
Infinite input resistance mean that input current flow is very minute, almost zero. This property shows that Op-Amp is a Voltage-Controlled device.
When output Impedance/resistance is zero, it mean that Output Voltage is not dependant on the Load connected at output.
When we say that its Gain is infinite, it does not mean that a very small input will be amplified to very high voltage at Output. Maximum value of the output is limited to the Power supply of Op-Amp. If gain is 106 then 1 μV at input will give 1 V at output.
This figure shows the typical block diagram of an most common type if Operation Amplifier. There are two inputs, Inverting and Non-Inverting. There is a single Output. And there two inputs for the Positive and Negative power Supplies.
Non Inverting Input: If a signal is applied at this input a signal of same polarity is produces at the output terminal.
Inverting Input: If a signal is applied at the inverting- input terminal, a signal of opposite polarity is produced at the output terminal. In case of sinusoidal input, a signal having phase difference of 180° shifted will be produced at output terminal.
Out Put: As this amplifier is a differential amplifier. This mean if v1 signal is applied at the inverting input and v2 is applied at the non-Inverting input, difference of two voltages will be applied at the input of amplifier, and output will depend upon this difference of voltages, multiplied by the gain(AV) of the amplifier. output vo = Av(v2-v1).
Op-Amp Power supply
Op-amp has two supply inputs. V+, V-. Op-Amp can be connected to power supplies in either of following ways.
Op-Amp Parameters
The parameters described below are very necessary to understand the basic concepts of the Op-Amp operation.
- Gain.
As it has been already stated the an ideal Op-Amp has Infinite op-loop differential gain. But practical Op-Amps have the Finite Gains. It can between 25,000 to 3,00,000.
Gain is expressed and manipulated in decibels (dB). If v1 and v2 are the input voltages then gain in dB will be:
Gain(dB) = 20log10 .
- Input Resistance
According to specifications of an ideal Op-Amp, Input resistance of the Op-Amp is infinitely high. But in real practice it falls in the range of 250 KΩ to 40 MΩ, for the Op-Amps with input stage made with Bi-Polar Transistors. For the Op-Amps with Field Effect Transistors(FET) input it can be 1012Ω.
- Output resistance
For an ideal Op-Amp Output resistance is zero. Practically it is not possible. As discussed earlier, Op-Amp is a Voltage Amplifier. Therefore it should have Output resistance as low as possible. Practical Op-Amp’s Output resistance is of the order of 100Ω.
- Common Mode Rejection Ratio (CMRR)
- Output voltage of an Op-Amp is proportional to the difference between the Input voltages applied to the inverting and non-inverting inputs. These input signals are called common mode signals.
- Ideally when two applied voltages are equal, the output voltage should be equal to zero.
- In the real case if Noise signal gets applied to both inputs, then it should not appear at the output.
- In practical such signals are not completely cancelled out. At it exists at the output as a unwanted noise.
- So the ability of cancelling out common mode signals at output is considered as an important property of Op-Amp and expressed in term of Common Mode rejection ratio(CMRR).
CMRR = =
The Common mode rejection ratio is also expressed in term of decibels
CMRR = 20 log10 dB.
Op-Amp can have a common mode rejection ratio of 90 dB.
- Slew Rate
It is the maximum rate of change at which, output voltage is capable of changing. It is expressed as V/μs. As an example μA 741 Op-Amp has slew rate of 0.5 μA.
The slew rate is the main hurdle in the way of maximum operating frequency of the Op-Amp. So slew rate can be used to determine the maximum operating frequency of OP-Amp.
fmax =
- Bandwidth
Bandwidth of an ideal Op-amp is Infinite. In real case open loop gain is not constant at all frequencies. It falls off at higher frequencies, due to capacitive effect.
- Input Offset Voltage
Ideal Op-Amp should give output voltage equal to zero, when value of applied voltage to both inputs is zero. However practically it is found that some output voltage does exist for zero input voltage. It is normally in the range of 10 μV to 7 mV. Input offset voltage is defined as output voltage for zero input voltage divided by the open-loop voltage gain of the Op-Amp.
- Input Bias Current
Base Bias currents of the both transistors of input differential amplifier should be equal. Due to some manufacturing imperfection there is always some difference between the two currents. These currents must be same for balanced operation of Op-Amp.
- Input Offset Current
The difference between the Bias currents is known as input Offset current. It value is 3-20 nA for Op-Amp with bipolar transistor inputs.
Virtual Ground and Summing Point
Before moving to applications of Op-Amp, learning about Virtual Point and Summing Point is required.
Input to the Op-amp is V1, and a feedback from output is being added to the Input at point A. This point is called summing point.
Input voltage Vi at the inverting terminal of Op-Amp is made such a small value that its value may be assumed as zero. Point A is at ground level. So point A is referred as Virtual Ground. But remember that it is not actual Ground point.
Inverting Amplifier
A configuration of an inverting amplifier is shown in the Fig.9, by using a Op-Amp.
In the figure Non-Inverting Terminal is grounded. Input signal Vin in being applied to inverting input through resistor R1. Resistor Rf feedbacks the output to the inverting input of Op-Amp.
Since point A is the virtual ground so:
Vin = I1 . R1 or I1 =
VO = - I2 . Rf or I2 = -
Practically Power drawn by the inverting input is zero. So all input current flows through Rf. Therefore I1 = I2 so = -
From above equation we get,
VO =- Vin also it can be written as = -
But voltage gain Av = so Av = -
This equation shows that Gain of the Op-Amp can be set / determined by the dividing the value of R2 by R1. The Negative sign shows that output of the inverting amplifier is 180° out of phase fron the input signal.
The open loop and closed loop gain. The open loop voltage gain (AOL) of an Op-Amp is the gain that is measured, when there is no feedback path between output and input.
If a feedback path exists between the output and input, then circuit’s gain is called closed-loop gain (ACL).
Input Resistance (Rin). As input resistance of OP-Amp is very high. In the circuit of Inverting amplifier, the R1 is the resistance connected between the input signal and virtual ground. So voltage source at input finds the input resistance as a parallel combination of R1 and Input resistance of Op-Amp. As input resistance of Op-Amp is very high than R1, so Input resistance of inverting Op-Amp is, Rin = R1 .
Output Resistance. As output resistance of the inverting amplifier is the parallel combination of Rf and output resistance of Op-Amp itself. Since the O/P resistance of the Op-Amp is very low, In the Inverter Amplifier case it becomes less than O/P resistance.
Common Mode Rejection Ratio. CMRR in the case of Inverting Amplifier is: CMRR =
Here ACL is closed loop gain of Inverting Amplifier.
ACM is the common mode gain of the Op-Amp
Example: Find the maximum allowable value of Vin
For the circuit shown. Assume the gain of Amplifier
Is 200.
Solution: It is given that ACL = 200, and Vo + 8V.
As Av =
So 200 = - = -
So Vin = - = - 0.04V = -40 mV.
Non-Inverting Amplifier
A configuration of a non - inverting amplifier is shown in the Fig.10, by using a Op-Amp.
In the figure, Input signal Vin in applied to non-inverting input of Op-Amp. Resistor R1 Is connected to Ground. Resistor R2 is a feedback resistor between output and inverting input of Op-Amp.
The output attempts to do whatever is necessary to make the voltage difference between the inputs zero. The voltage gain of a real op-amp is so high that a fraction of a milli-volt input will swing the output over its full range. Therefore difference between the voltages at the both inputs is so small that they can be considered equal.
Vin = Vi
If I1 is the current flowing through R1 then I1 = or Vin = I1 . R1 …….i
Since the voltage drop across R2 is equal to Vo - Vin
So Current through resistor R2 will be: I2 = or I2 . R2 = VO - Vin
Therefore VO = Vin + I2 . R2
Practically Power drawn by the inverting input is zero. So I1 and I2 are considered equal as same current passes through R1 and R2.
Therefore I1 = I2 so replacing I2 by I1 in above equation we get,
VO = Vin + I1 . R2 …………….ii
Amplifier Voltage Gain, AV = =
Putting Values of VO and Vin in the above equation we get
AV =
Putting the values of VO and Vin we get
Av = = =
Av = 1 + This is the equation for the gain of Non Inverting Amplifier.
Note that the gain of Non-inverting Amplifier is greater than the gain of Inverting Amplifier.
Input Resistance. Note that input signal is applied directly to the input of Op-Amp. Therefore input resistance of Non-Inverting Amplifier is very high.
Output Resistance. Output resistance of Non-Inverting Amplifier is less than the output resistance of the Op-Amp itself.
Common Mode Rejection Ratio. CMMR =
Example. Find the value of close loop gain (ACL), Common Mode Rejection ratio, and maximum Operating frequency of the non-Inv-Amplifier, ACM = 0.001, and slew rate = 0.5V/μs.
Solution. It is given that ACM = 0.001, R1 = 10K,
R2 = 100K, RL = 10K , VIN = 1VPP.
Closed-loop gain of N-Inv-Amp ACL = 1 +
= 1 + = 1 + 10 = 11
Common Mode Rejection Ration CMMR =
ACL = 11, and ACM = 0.001
So CMMR = = = 11,000.
We know that VIN = 1VPP and ACL = 11 so VOUT = 1 x 11 VPP = 11 VPP
From VPP we can find VP K = 5.5
And Maximum Frequency fMAX = = = = 14.47 x 103 Hz.
= 14.47 KHz.
Voltage Follower.
The Non-Inverting Amplifier is modified
As shown in the Fig.11, to make a Voltage
|
Follower Amplifier. Notice that output is directly
Connected to the Inverting Input of the Op-Amp.
Equation for voltage gain is Av = 1 +
Here R1 = R2 = 0 so we get Av = 1
It acts as a Buffer Amplifier. This voltage follower has very high Input Impedance and veru low output Impedance.
CMMR = = As closed loop gain (ACL) is equal to 1.
- For the Voltage Follower shown, find the value of ACL, CMMR, and fmax.
ACM = 0.001, AOL = 180,000, ZIN = 1M, ZOUT = 80M, Slew Rate = 0.5 V/μs, VIN = 6VPP,
As ACL = 1 + , for Voltage follower R1 = R2 = 0
So ACL = 1,
CMMR = = = 1000.
To calculate Maximum Operating Frequency
VIN = 6VPP, ACL = 1,
So VOUT = 6 x 1 = 6VPP
Thus Peak Output voltage = 3VPK and
fMAX = = = = 26.5 KHz Hz.
Summing Amplifier(Inverting).
|
The Summing Amplifier is a very flexible circuit based upon the standard Inverting Operational Amplifier configuration. As its name suggests, the “summing amplifier” can be used for combining the voltage present on multiple inputs into a single output voltage.
If R1 = R2 = R3 then VO = - (V1 + V2 + V3)
(Derivation has not been shown)
Summing Amplifier(Non-inverting).
|
Without showing the derivation the value of
Output is,
VO = (1 + )( )
|
Without showing the derivation the value of
Output is,
If RF = R1, Then VO = (V2 -V2)
Differential Amplifier.
|
Fig. 14 shows the circuit of a Differential Amlifier.
If V1 and V2 is applied at the inputs of the Amplifier
Then Vo will be equal to the difference between the
Two voltages applied at the inputs.
If R1 = R3, and R2 = R4 then
AV = and VO = (V2 - V1)
|
Integrator Amplifier.
Fig. 15 shows the circuit of a Integrator Amlifier.
It will produce Vo which will be the Integration of the Vin.
Vo = -
Differentiator Amplifier.
|
Fig. 16 shows the circuit of a Differentiator Amlifier.
It will give Vo at output whill will be differenciation of Vin.
Vo = -R1C1